Re^3: Complex structures and function "map"

map doesn't store anything, it returns a list. What list do you want it to return, a list of references to arrays?

sub func {
   ...
   return \@a;
}

map { func(...) } ...
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sub func {
   ...
   return [ ... ];
}

map { func(...) } ...
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sub func {
   ...
   return ...;
}

map { [ func(...) ] } ...
[download]

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Re^4: Complex structures and function "map" by nando (Acolyte) on Oct 21, 2011 at 20:48 UTC
Great! Yes I feel that I did not explained correctly. Sometimes I do not know if Google Translator is a help or an additional problem. I would like to achieve a structure "@ array" whose elements were other arrays. As I was reading this afternoon, this is achieved by references, that being scalars, can be elements of an array. So ... 澠 can by "map" to get from the output of the "fileparse" (a list of three scalar), an @array structure ($scalar1, $scalar2, ... $scalarn) where $scalarn is a reference to the list ($name, $path, $suffix)? Perhaps the question does not even make sense, I'm blocked today :) Thanks for your effort to understand	[reply]
Re^5: Complex structures and function "map" by ikegami (Patriarch) on Oct 23, 2011 at 10:56 UTC
Sorry, I hadn't noticed you had replied. I would like to achieve a structure "@ array" whose elements were other arrays. As I was reading this afternoon, this is achieved by references, that being scalars, can be elements of an array. Correct. So ... 澠 can by "map" to get from the output of the "fileparse" (a list of three scalar), an @array structure ($scalar1, $scalar2, ... $scalarn) where $scalarn is a reference to the list ($name, $path, $suffix)? Close. One can't create a reference to a list. You'll need to store `$name, $path, $suffix` in an array, and return a reference to that array. The three snippets I posted show ways of doing that. So map will end up returning a list of references to arrays. Like subs, it cannot return an array, but you can store the list in an array. I feel that I did not explained correctly. Your post did not change my understanding of the question.	[reply] [d/l]