Re: Substituting a comma only when it is preceded and followed by a bracket



use Modern::Perl;

$_= 'blah blah, blah blah blah (blah, blah, blah), blah, blah';

while($_=~ s@\(([^\)]*?)h,@\($1h;@gs){}

say;
[download]

Output : blah blah, blah blah blah (blah; blah; blah), blah, blah
Not quite what was asked for, but it does produce the requested output :P

Comment on Re: Substituting a comma only when it is preceded and followed by a bracket Download Code

Replies are listed 'Best First'.
Re^2: Substituting a comma only when it is preceded and followed by a bracket by Logicus (Initiate) on Nov 03, 2011 at 01:57 UTC
Here's the proper one; `while($_=~ s@$([^$]*?),@\($1;@gs){}` [download]	[reply] [d/l]
Re^3: Substituting a comma only when it is preceded and followed by a bracket by Logicus (Initiate) on Nov 03, 2011 at 02:08 UTC
Oh hang on, ok there was no check to see if the comma was followed by a bracket, so if there was no close bracket, it would replace every comma to the right of the open bracket, which technically would be incorrect because the task specified there to be a following bracket and a single bracket by itself would not count. However as long as the two brackets are there it works fine.	[reply]

Replies are listed 'Best First'.
Re^2: Substituting a comma only when it is preceded and followed by a bracket by Logicus (Initiate) on Nov 03, 2011 at 01:57 UTC
Here's the proper one; `while($_=~ s@\(([^\)]*?),@\($1;@gs){}` [download]	[reply] [d/l]
Re^3: Substituting a comma only when it is preceded and followed by a bracket by Logicus (Initiate) on Nov 03, 2011 at 02:08 UTC
Oh hang on, ok there was no check to see if the comma was followed by a bracket, so if there was no close bracket, it would replace every comma to the right of the open bracket, which technically would be incorrect because the task specified there to be a following bracket and a single bracket by itself would not count. However as long as the two brackets are there it works fine.	[reply]