in reply to Extracting Log File data for a given date range

Not really that hard. Convert your from and to dates to something you can sort on (YYYY-MM-DD), then pattern match each line, convert the date there as well, and compare. When testing this, make sure to call the Perl script with the from and to dates as arguments and in the format specified by the OP.

use strict; use warnings; { my %mon = ( 'JAN' => 1, 'FEB' => 2, 'MAR' => 3, 'APR' => 4, 'MAY' => 5, 'JUN' => 6, 'JUL' => 7, 'AUG' => 8, 'SEP' => 9, 'OCT' => 10, 'NOV' => 11, 'DEC' => 12 ); sub convDate { my $d = [split /-/, $_[0]]; return sprintf('%04d-%02d-%02d', $d->[2], $mon{uc $d->[1]}, $d->[0]); }} my $from = convDate($ARGV[0]); my $to = convDate($ARGV[1]); my @d = <DATA>; for (@d) { if (m/(\d+-\w+-\d+)_\d+\.\d+\.\d+/g) { print if convDate($1) ge $from && convDate($1) le $to; } } __DATA__ ABC01, 91XYZ889=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 02-Dec-2011_ +00.34.51, bigFatLog_02-Dec-2011_00.34.06.log ABC03, 93XYZ272=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 07-Dec-2011_ +09.21.58, bigFatLog_07-Dec-2011_09.20.57.log ABC02, 93XYZ807=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 08-Dec-2011_ +23.00.15, bigFatLog_08-Dec-2011_22.59.34.log ABC05, 91XYZ525=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 10-Dec-2011_ +10.01.36, bigFatLog_10-Dec-2011_10.01.00.log ABC01, 93XYZ252=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 12-Dec-2011_ +11.58.23, bigFatLog_12-Dec-2011_11.57.20.log ABC03, 93XYZ543=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 12-Dec-2011_ +23.34.07, bigFatLog_12-Dec-2011_23.33.23.log ABC04, 92XYZ066=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 13-Dec-2011_ +01.00.31, bigFatLog_13-Dec-2011_00.59.29.log ABC05, 93XYZ184=_=SOMEBODY.NAME@DOMAIN.COM, HighPriority, 13-Dec-2011_ +01.54.41, bigFatLog_13-Dec-2011_01.54.04.log