Re: unshifting by reference

unshift(@($this->{Memory}),$this->{Senses});
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To dereference the array ref, you need curlies, not parentheses, i.e. @{$this->{Memory}}

my $this = {
    Memory => ["foo"],
    Senses => "bar",
};

unshift @{$this->{Memory}}, $this->{Senses};

use Data::Dumper; print Dumper $this;

__END__
$VAR1 = {
          'Senses' => 'bar',
          'Memory' => [
                        'bar',
                        'foo'
                      ]
        };
[download]

Comment on Re: unshifting by reference Select or Download Code

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Re^2: unshifting by reference by palkia (Monk) on Dec 16, 2011 at 00:43 UTC
Thx it works (obvious it was ^^). But I don't et it, I thought that the "->" dereferences, doesn't it ? when I did `print $this->{N}[0]{Value};` it worked ok, so whats the difference ? Why didn't I needed to dereference there ? and whats "Dumper" is this really required ? (I prefer to avoid module dependencies) Thx again	[reply] [d/l]
Re^3: unshifting by reference by Eliya (Vicar) on Dec 16, 2011 at 00:51 UTC
The thing is that `unshift` needs an array (syntactically), not an array reference. And the way to get an (entire) array from a reference is to say `@$aref`, or `@{ $something->{that}{returns}[1]{aref} }` for more complex expressions. To address a single element of the array, you'd say `$aref->[$index]`. (The Data::Dumper module is to easily print out complex data structures. I just used it for demo purposes — you of course don't need it to unshift the value.)	[reply] [d/l] [select]
Re^3: unshifting by reference by ikegami (Patriarch) on Dec 16, 2011 at 01:36 UTC
`->` is dereferencing a hash that has nothing to do with your question. Your question is about dereferencing the array referenced by `$this->{N}`.	[reply] [d/l] [select]
Re^3: unshifting by reference by ikegami (Patriarch) on Dec 16, 2011 at 01:37 UTC
`->` is dereferencing a hash that has nothing to do with your question. Your question is about dereferencing the array referenced by `$this->{N}`.	[reply] [d/l] [select]