in reply to Surprised by Perl parse of ternary operator

Running this line of code through MO=Deparse produced the same output.

Add -p to show the precedence: 

c:\test>perl -MO=Deparse,-p -e"$fred == 42 ? $config = 'k1' : $config 
+= 'k2';"
((($fred == 42) ? ($config = 'k1') : $config) = 'k2');
-e syntax OK

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(And yes. It's weird :)

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