Re^2: Can an element be created because it was accessed ?

exists( $a[$i] ) doesn't return whether an element exists in an array or not as its name implies, and it's deprecated for that very reason.

Use $i < @a instead.

if ( $1 < @{ $this->{N} }) { my $testedNVal = $this->{N}[$1]{Val}; ... }
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Re^3: Can an element be created because it was accessed ? by NetWallah (Canon) on Dec 29, 2011 at 03:46 UTC
That wont work if the array is intentionally sparse. Depending on how the O.P enters data into the array, "defined" may be a reasonable choice. "Battle not with trolls, lest ye become a troll; and if you gaze into the Internet, the Internet gazes also into you." -Friedrich Nietzsche: A Dynamic Translation	[reply]
Re^4: Can an element be created because it was accessed ? by ikegami (Patriarch) on Dec 29, 2011 at 04:33 UTC
That wont work if the array is intentionally sparse. This is not a supported "feature". It's the side effect of a bug in `exists`. But my fix was wrong. (I've been fixing uses of `exists` to check if an element exists.) It should be `if ( defined( $this->{N}[$1] ) ) { my $testedNVal = $this->{N}[$1]{Val}; ... }` [download] And in all likelyhood, the following would also do the trick: `if ( $this->{N}[$1] ) { my $testedNVal = $this->{N}[$1]{Val}; ... }` [download]	[reply] [d/l] [select]