in reply to limit of for loop!!

What are you actually trying to do? What precision (how many digits) do you really need? Moritz provided a good solution (work with integer values then scale as the last step) - what is wrong with that solution?

As an exercise try writing 1/3 as a decimal fraction in full. Let me get you started:

0.33333333333333333333333333333

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Have you figured out that you can't exactly represent 1/3 as a finite decimal fraction? In the same way you can't exactly represent 1/10 (base 10) as a finite binary fraction. This seems like a problem, but for almost all real applications for arithmetic it is not an issue. You seldom need more than a few digits of precision for an answer (although for some calculations you may need more precision for intermediate answers).

So the key questions are: what are you trying to do and how much precision do you really need? There are many possible ways to solve your problem, but a solution depends very much on what you are trying to achieve.

True laziness is hard work

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Re^2: limit of for loop!!
by sagar123 (Novice) on Jan 02, 2012 at 07:31 UTC
    HI,

    I need some value upto 3 decimal places and want to use that in calculations. But actually the value becomes 22.430000001 like that. in summary I want that value remains 22.43 just not "nice value" to be 'printed'. yes 22.43 and 22.43000001 are almost same. but I need to extract some data from million number of values (which are three decimal place) from text file. So I need exact decimal place or it will be ignored to be extracted.

    As suggested I will divide 22430 by 1000, that will be a good option

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