Re^2: Range Operator in If Statement

Hey perlbotics, thanks for you QUICK reply...

Ohh ok I thought I could use the range operator for this type of thing, but guess not.

I wanted to use that because it seemed like it was the "shorthand" way of doing it.
Wanted a short way because I needed a whole bunch of those statements and I didn't want to have a ton of these statements:

if ($ref >= 1 && $ref <= 8) { ...... }
if ($ref >= 9 && $ref <= 16) { ...... }
if ($ref >= 17 && $ref <= 24) { ...... }
if ($ref >= 25 && $ref <= 32) { ...... }
#....more checks
[download]

But if that's what you recommend then I'll just use my original way I had like above and like you had...

Thanks again for the reply,
Matt

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Re^3: Range Operator in If Statement by Marshall (Canon) on Jan 04, 2012 at 21:34 UTC
This looks like a power of 2 problem. If you could give us some more detail about what you are doing, I think some very efficient solutions might be forthcoming.	[reply]
Re^3: Range Operator in If Statement by LanX (Saint) on Jan 05, 2012 at 01:56 UTC
When classifying by intervals, better try `$case = int( ($ref-1) / 8 )` , so you only have to test for the results 0,1,2,3... `DB<104> for $ref (1,8,9,16,17,24,25,32) { print "$ref: ", int(($ref-1) +/8), "\n" } 1: 0 8: 0 9: 1 16: 1 17: 2 24: 2 25: 3 32: 3` [download] Cheers Rolf	[reply] [d/l] [select]
Re^3: Range Operator in If Statement by ambrus (Abbot) on Jan 05, 2012 at 11:43 UTC
If you have multiple consecutive intervals, it's better to use an elsif cascade, such as `if ($ref <= 8) { say "ref is at most 8."; } elsif ($ref <= 16) { say "ref is above 8 but at most 16." } elsif ($ref <= 24) { say "ref is above 16 but at most 24." } elsif ($ref <= 32) { say "ref is above 24 but at most 32." } else { sat "ref is above 32." }` [download] The `elsif` part means that if the previous condition was found true, the next one is not tested for, so eg. if `$ref = 5` then the first branch is executed, the rest of the tests and branches are skipped.	[reply] [d/l] [select]