in reply to Why is const x const not a const?
Do you mean: why isn't constant-folding applied to x?
It is odd that it doesn't. Maybe its weird «( EXPR ) x EXPR» syntax interferes? I doubt it, though. It was probably just overlooked.
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Re^2: Why is const x const not a const?
by The Perlman (Scribe) on Jan 23, 2012 at 00:59 UTC | |
by ikegami (Patriarch) on Jan 23, 2012 at 09:37 UTC | |
by moritz (Cardinal) on Jan 23, 2012 at 09:50 UTC | |
by ikegami (Patriarch) on Jan 23, 2012 at 18:37 UTC | |
by moritz (Cardinal) on Jan 23, 2012 at 19:11 UTC | |
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by BrowserUk (Patriarch) on Jan 23, 2012 at 18:43 UTC | |
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by BrowserUk (Patriarch) on Jan 23, 2012 at 10:10 UTC | |
by LanX (Saint) on Jan 24, 2012 at 14:05 UTC | |
Re^2: Why is const x const not a const?
by PerlGrey (Initiate) on Jan 24, 2012 at 17:03 UTC | |
by Eliya (Vicar) on Jan 24, 2012 at 18:41 UTC | |
by ikegami (Patriarch) on Jan 24, 2012 at 20:59 UTC |