in reply to Efficiency of implementation

save 0.5 *4^7 *4^7 entries to RAM

If every entry were just 1 byte, that would amount to: 745,058 GB or 727 TeraBytes.

To my knowledge, there is no (micro)processor yet made that can address that much virtual memory, let alone physical ram.

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.

The start of some sanity?

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Re^2: Efficiency of implementation
by azheid (Sexton) on Jan 31, 2012 at 20:06 UTC

    4^7*4^7 * 4bytes per float =~1.07Gb

    Did I do that computation incorrectly? I have 8 gb of ram. I am pretty sure 1 scalar is 4 bytes, so that should be within the acceptable range?

[reply]

      Sorry. I took your 4^7 to be shorthand for 4*10^7. My mistake.

      With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
      Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
      "Science is about questioning the status quo. Questioning authority".
      In the absence of evidence, opinion is indistinguishable from prejudice.

      The start of some sanity?
[reply]
Re^2: Efficiency of implementation
by azheid (Sexton) on Jan 31, 2012 at 19:57 UTC

    Color me embarrassed for not checking the actual size of that computation. Sorry to waste your time.

[reply]

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