Re: Hash Printing reveals Hash Memory Location

if (($english && $foreign) eq '-1') {
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The expression $english && $foreign will evaluate to either true (1) or false ("") but will never be equal to '-1'.

sub hash_processor::function () { my ($english, $foreign, $process) = @_;
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Your prototype says that the subroutine accepts no arguments but the next line says that your subroutine does accept three arguments. You shouldn't use prototypes.

You are using package names but I don't see where you are creating a package namespace.

if ($process == '0') {
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That is usually written as $process == 0 or $process eq '0' depending on whether $process contains a string or a number.

$english = "$english" . "$hash_processor::tag_count"; $foreign = "$foreign" . "$hash_processor::tag_count";
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That is usually written as:

   $english .= $hash_processor::tag_count;
   $foreign .= $hash_processor::tag_count;
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Comment on Re: Hash Printing reveals Hash Memory Location Select or Download Code

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Re^2: Hash Printing reveals Hash Memory Location by tobyink (Canon) on Feb 03, 2012 at 07:51 UTC
The expression $english && $foreign will evaluate to either true (1) or false ("") but will never be equal to '-1'. Wrong. The "&&" operator doesn't return 1 or "". It returns the expression on the right side of "&&" if and only if both expressions are true. `use 5.010; my $english = 'foobar'; my $foreign = -1; say ($english && $foreign); # says "-1" say ($foreign && $english); # says "foobar"` [download]	[reply] [d/l]
Re^3: Hash Printing reveals Hash Memory Location by lidden (Curate) on Feb 04, 2012 at 00:59 UTC
It returns the expression on the right side of "&&" if and only if both expressions are true. It returns the expression on the right side if the expression on the left side is true. `$ perl -E 'say "Yes" if "Foo" && 0 eq 0' # says "Yes" $ perl -E 'say "Yes" if "Foo" && "" eq ""' # says "Yes" $ perl -E 'say "Yes" if "Foo" && 0 eq ""' # Nothing` [download]	[reply] [d/l]
Re^2: Hash Printing reveals Hash Memory Location by AnomalousMonk (Archbishop) on Feb 03, 2012 at 19:22 UTC
You shouldn't use prototypes. For a discussion of why you shouldn't use prototypes unless you really know what you're doing, see Far More than Everything You've Ever Wanted to Know about Prototypes in Perl -- by Tom Christiansen (especially the section "Prototype Problems") in the Tutorials Subroutines area.	[reply]