in reply to Re: Trying to understand (caller($i))[4], a.k.a. $hasargs [solution]
in thread Trying to understand (caller($i))[4], a.k.a. $hasargs

Excellent! Yes, that stops the error entirely. I'll submit it to DC as a patch. Thanks for the code.

  • Comment on Re^2: Trying to understand (caller($i))[4], a.k.a. $hasargs [solution]