Re: new to perl, syntax question

The index expression of $array[ EXPR ] is evaluated in scalar context, and the an array in scalar context evaluates to the number of elements in the array.

my @folder = qw( a b c d e f );
my @name   = qw( x y z );
my $var = $folder[@name];   # $var = 'd', since @name == 3.
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Re^2: new to perl, syntax question by tics (Initiate) on Feb 21, 2012 at 06:44 UTC
Thanks ikegami, for the wonderful explanation ! And I really appreciate the example. It really helps a lot. And thanks for the other suggestions as well. I'm really glad I chanced upon this forum. I did thought of making use of print to try figuring out what the statements would do, but the Internet connection here is really awful. So I gave up downloading Strawberry Perl. Only could resort to trying to understand the code using Notepad++.	[reply]

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Re^2: new to perl, syntax question
by tics (Initiate) on Feb 21, 2012 at 06:44 UTC

Thanks ikegami, for the wonderful explanation ! And I really appreciate the example. It really helps a lot.

And thanks for the other suggestions as well. I'm really glad I chanced upon this forum. I did thought of making use of print to try figuring out what the statements would do, but the Internet connection here is really awful. So I gave up downloading Strawberry Perl.

Only could resort to trying to understand the code using Notepad++.

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