Re^2: this doesn't sort

Yes, That did it perfectly! :-) Thank you!

But I don't understand it! I can't even make syntactic sense out of it. :-(

I tried replacing $a->[$sortNdx] with [$a][$sortNdx], which I thought would be syntactically the same thing, but got a syntax error.

Could you explain to me what's going on?

Thanks.

Comment on Re^2: this doesn't sort

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Re^3: this doesn't sort by moritz (Cardinal) on Feb 26, 2012 at 06:42 UTC
Inside the sort block, `$a` and `$b` are elements of `@bigArray`, not indexes into it. So if `@bigArray` contains array refs, both $a and $b end up being an array ref. And you can dereference and index into an array with the `$a->[$index]` syntax. On the other hand if you write `[$a]`, you wrap the array ref in $a into another array ref -- not what you want. See perlreftut and perlref for more details. Perl 6 - second systems done right	[reply] [d/l] [select]
Re^4: this doesn't sort by hsfrey (Beadle) on Feb 26, 2012 at 19:13 UTC
Thanks so much!	[reply]