Re: Perl "new" command

This:

Foo->bar($baz)

is basically just syntactic sugar for:

Foo::bar("Foo", $baz)

with one key exception: in the first example, if the "Foo" package doesn't have a sub called "bar", then the object-oriented concept of inheritance is used to search for it in some other packages.

So in your example, the list of keys accepted by StatView::Script->new can probably be seen by examining the new sub in the StatView::Script package.

Comment on Re: Perl "new" command Select or Download Code

Replies are listed 'Best First'.
Re^2: Perl "new" command by akagrawal3 (Beadle) on Mar 01, 2012 at 10:19 UTC
`Foo::bar("Foo", $baz)` what is Foo here. Is it a name of a routine or just a typical scalar value?	[reply] [d/l]
Re^3: Perl "new" command by tobyink (Canon) on Mar 01, 2012 at 11:31 UTC
The first `Foo` is the name of a package, as in... `package Foo; sub bar { print "Inside the package, I am called 'bar'\n"; print "But outside the package, I am called Foo::bar\n"; }` [download] The second "Foo" is just a string scalar. I really think you need to read perlboot from start to finish.	[reply] [d/l] [select]
Re^4: Perl "new" command by JavaFan (Canon) on Mar 01, 2012 at 11:42 UTC
In that example, the sub can be called as `Foo::bar()` regardless whether you are inside or outside the package. It's just that inside the package, the sub can also be called as `bar()`.	[reply] [d/l] [select]