In general, if you want to find the last pattern in a string:

/.*PAT/s;
[download]

So, in your case:

s/(.*)\).*/$1/s;
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You can also combine this with the \K construct:

s/.*\K\).*//s
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BTW, your question makes it unclear to me whether you want to trailing newline to be removed. My code does, and your "want it to be" does not include a newline -- but your original solution does.