How to escape out *?+ in strings for substit.

bagel has asked for the wisdom of the Perl Monks concerning the following question:

My code is at http://24.167.156.45 it accepts 2 inputs for the log file (access_log) and something to search for (127.0.0.1) and then commences to replace it. I did this by having the file fed into an array and substituting the matching lines with "". The only problem is since these are GET requests in a log ?, *, + show up often but PERL complains out. Any solution?

Comment on How to escape out *?+ in strings for substit.

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Re: How to escape out *?+ in strings for substit. by japhy (Canon) on Jul 12, 2001 at 08:12 UTC
Use either the `quotemeta()` function, or the `\Q...\E` escape sequences. `$string =~ /\Q$text\E/; # or $safe = quotemeta $text; $string =~ /$safe/;` [download]	[reply] [d/l]

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