How CPAN identifies a package as a module or documentation?

glasswalk3r has asked for the wisdom of the Perl Monks concerning the following question:

Greetings fellow monks,

I'm asking myself how CPAN identifies that a package is a Module or Documentation. I release a distribution to it (Siebel-Srvrmgr-0.02) and there are two packages identified as "Documentation" (Siebel::Srvmrgr::Regexes and Siebel::Srvrmgr::ListParser::Output::Listcomp) and one package (Siebel::Srvrmgr) that is really only documentation (POD) and is identified as a module.

How does CPAN classify that? There is any way to control such categories? I tried to find something related but got nothing.

Regards,

Alceu Rodrigues de Freitas Junior
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"You have enemies? Good. That means you've stood up for something, sometime in your life." - Sir Winston Churchill

Comment on How CPAN identifies a package as a module or documentation?

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Re: How CPAN identifies a package as a module or documentation? by JavaFan (Canon) on Mar 16, 2012 at 15:44 UTC
one package (Siebel::Srvrmgr) that is really only documentation (POD) and is identified as a module. Yet, that .pm file starts with `package Siebel::Srvrmgr; our $VERSION = '0.02';` [download] Which magic do you expect the CPAN indexer to have? Now, I do not claim to know how the indexer works, but I would try putting documentation only in a file whose name end with `.pod` instead of with `.pm`	[reply] [d/l] [select]
Re^2: How CPAN identifies a package as a module or documentation? by Anonymous Monk on Mar 16, 2012 at 21:07 UTC
FWIW, search.cpan.org's indexer is generally not referred to as the "CPAN Indexer", and its mostly closed-source ( see How does the CPAN indexer determin documentation ) On the other hand https://metacpan.org/release/Siebel-Srvrmgr only lists modules	[reply]