Re^4: I can't see why this shorthand doesn't behave like the verbose form

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Re^5: I can't see why this shorthand doesn't behave like the verbose form by Anonymous Monk on Mar 25, 2012 at 17:13 UTC
:) I wonder what happens when you get rid of them $ perl -le " eval my $foo = 1; " Can't modify eval "string" in scalar assignment at -e line 1, near "1; +" Execution of -e aborted due to compilation errors. $ perl -MO=Deparse,-p -le " eval my $foo = 1; " Can't modify eval "string" in scalar assignment at -e line 1, near "1; +" -e had compilation errors. BEGIN { $/ = "\n"; $\ = "\n"; } (eval(my $foo) = 1); $ perl -le " eval( my $foo = 1;) " syntax error at -e line 1, near "1;" Execution of -e aborted due to compilation errors. $ perl -le " eval( my $foo = 1) " $ perl -le " eval( my $foo = q/print 666/ ) " 666 [download] Uh oh :)	[reply] [d/l]

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Re^5: I can't see why this shorthand doesn't behave like the verbose form
by Anonymous Monk on Mar 25, 2012 at 17:13 UTC

:) I wonder what happens when you get rid of them

$ perl -le " eval my $foo = 1; "
Can't modify eval "string" in scalar assignment at -e line 1, near "1;
+"
Execution of -e aborted due to compilation errors.

$ perl -MO=Deparse,-p -le " eval my $foo = 1; "
Can't modify eval "string" in scalar assignment at -e line 1, near "1;
+"
-e had compilation errors.
BEGIN { $/ = "\n"; $\ = "\n"; }
(eval(my $foo) = 1);


$ perl -le " eval( my $foo = 1;) "
syntax error at -e line 1, near "1;"
Execution of -e aborted due to compilation errors.

$ perl -le " eval( my $foo = 1) "

$ perl -le " eval( my $foo = q/print 666/ ) "
666
[download]

Uh oh :)

[reply]
[d/l]