Re: Sub ref from string without eval

I suspect this is an XY Problem, but you can do this using Symbolic references. This will not work with strict refs in place (you do use strict, right?), so your code might look like
my $x = 'Foo'; my $sub_ref = do { no strict 'refs'; \&{$x}; };
[download]
so your code might look like

my $x = 'Foo';

my $sub_ref = \&{$x};
[download]

Update: It appears my $sub_ref = \&{'Foo'}; passes strict when &{'Foo'}; does not. Huh?

#11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.

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Re^2: Sub ref from string without eval by moritz (Cardinal) on Apr 02, 2012 at 15:01 UTC
`\&{$x}` works perfectly fine with strict refs. It is only implicit usage of strings as references that is prohibted by strict refs. If you go to the length of writing `\&{ ... }`, perl assumes a symbolic reference is indeed what you want. `use strict; use warnings; use 5.010; sub Foo { 'in sub Foo' } my $x = 'Foo'; my $sub_ref = \&{$x}; say $sub_ref->(); __END__ in sub Foo` [download] Perl 6 - second systems done right	[reply] [d/l] [select]
Re^3: Sub ref from string without eval by ikegami (Patriarch) on Apr 02, 2012 at 19:09 UTC
It is only implicit usage of strings as references that is prohibted by strict refs. Nope. `$ perl -e'use strict; my $x = "foo"; \${ $x }' Can't use string ("foo") as a SCALAR ref while "strict refs" in use at + -e line 1. $ perl -e'use strict; \${ "foo" }' Can't use string ("foo") as a SCALAR ref while "strict refs" in use at + -e line 1.` [download] `\&{ ... }` is clearly an exception.	[reply] [d/l] [select]
Re^2: Sub ref from string without eval by kejohm (Hermit) on Apr 02, 2012 at 22:46 UTC
To quote strict: There is one exception to this rule: `$bar = \&{'foo'}; &$bar;` [download] is allowed so that `goto &$AUTOLOAD` would not break under stricture.	[reply] [d/l] [select]