Re: &&= vivify keys?

$x{a} &&= 1; is effectively the same as

$x{a} = $x{a} && 1;
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which is in this case

$x{a} = undef && 1;
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which is

$x{a} = undef;
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Re^2: &&= vivify keys? by oha (Friar) on Apr 18, 2012 at 09:10 UTC
so true! not sure why, but i was expecting it to be the same as `$x{a} && $x{a} = 1;` [download] thank you!	[reply] [d/l]
Re^3: &&= vivify keys? by ikegami (Patriarch) on Apr 18, 2012 at 21:16 UTC
Actually, you're closer to the truth than Eliya is. The assignment is indeed conditional. Aside from the syntax error from missing parens, the problems both yours and Eliya share are: `1` is actually evaluated before anything else, `$x{a}` is only evaluated once, and `$x{a}` is (only) evaluated in lvalue context. See Re^2: &&= vivify keys?.	[reply] [d/l] [select]