in reply to Re: How to replace on a smooth way?
in thread How to replace on a smooth way?

Thank you so much, but here comes the tricky part: I have to match "§" and in the replacement to use "& # 0167;" otherwise - either does not match for "& # 0167;", or replacing with "§" in it - brings strange prints

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Re^3: How to replace on a smooth way?
by MidLifeXis (Monsignor) on Apr 19, 2012 at 14:31 UTC

    The stuff within the parens is a capture - if you move the § outside of the capturing parenthesis, and then add your required entity to the replacement text, it should do what you need.

    So, if you have a replacement s/(A\S+)/[$1]/ and want to replace A with something else, you would use s/A(\S+)/[B$1]/ instead, replacing A and B as necessary.

    A read of perlre, perlrequick, and perlretut may be helpful. I also wonder if HTML::Entities may be a more appropriate solution to the second requirement.

    --MidLifeXis

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Re^3: How to replace on a smooth way?
by roboticus (Chancellor) on Apr 19, 2012 at 14:33 UTC

    bestsiteeditor:

    That sounds like you may have an encoding problem, then.

    ...roboticus

    When your only tool is a hammer, all problems look like your thumb.

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