in reply to /s option modifier in regex substitution
Is there a nicer or more idiomatic way to do this? Thanks.
No , its as straight forward as it gets
You could write __END__[.\n]* or the results of qr/.s/ (which are for perl 5.12 __END__(?s-xim:.)* and for perl 5.14 __END__(?^s:.)* ) but they're still hairy regexes
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