in reply to Re^3: How regex works in array mode?
in thread How regex works in array mode?

I already replace it and the output is: 
ip:192.168.243.1

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but it doesn't print the "ip:192.168.243.2" Is it possible to print the next value in the array? Thanks

or is this output possible?

ip:192.168.243.1 ip:192.168.243.2

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Re^5: How regex works in array mode?
by JavaFan (Canon) on Apr 26, 2012 at 10:02 UTC
    Perhaps you haven't replaced it correctly? 
    use 5.010;
my @lines = ("ip:192.168.243.1", "ip:192.168.243.2" =~
    /(ip:[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3})/);
say for @lines;
__END__
ip:192.168.243.1
ip:192.168.243.2

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    Do note that ip:192.168.243.2 is in @lines only because the pattern matches the entire string. And do note that "ip:192.168.243.1" is not subject to any matching. In fact, the assignment to @lines is equivalent with: 
    my @lines;
$lines[0] = "ip:192.168.243.1";
push @lines, $1 if "ip:192.168.243.2" =~ /(ip:[0-9]{1,3}\.[0-9]{1,3}\.
+[0-9]{1,3}\.[0-9]{1,3})/;

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