in reply to is it prime?

It cannot be correct. Have you actually tried this? Considering that any number is divisible by 1, isPrime will return 1 for each number. A fix is easy, have $i start at 2.

But then you are still far from being efficient. There's no need to loop to $num/2, you can stop at sqrt($num). There's no need to test even numbers (except 2). And there's no need to continue once you've found a divisor.

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Re^2: is it prime?
by Anonymous Monk on May 06, 2012 at 05:44 UTC
    i did test it, you are correct it is incorrect i was hoping for a fix (hence why i posted) thanks for the help
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      also you are right again i dont need a loop hell knows why i was using one sinse im only sending 1 arg (digit) at a time to the sub routine :/
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        no.. above was wrong.. jeez now i dont know what im talking about haha this isnt going good :/ not slept all night is my excuse!
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