in reply to Re^2: Robocopy log parsing
in thread Robocopy log parsing

I wanted $dir to get its value from extracting text from the New Dir entry. For each new Dir there will be a x:\....\ string of text to denote a folder path, which for each line where there is New Dir match it assigns the value found to $dir, then for each corresponding line the print join prints the $dir value. Well that was the idea in theory. If I remove the $dir from the print join statement, it works. Ok so $line fixed. but still having probs with $dir. Does the $dir =~ not declare it as an assignment?

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Re^4: Robocopy log parsing
by choroba (Cardinal) on May 28, 2012 at 15:53 UTC
    No, assignment operator is =, =~ is a pattern match operator. See perlop.
Re^4: Robocopy log parsing
by bit5nip3r (Initiate) on May 28, 2012 at 16:25 UTC

    Still does not work. can't extract text from a line based on a regexp. It does not get assigned to $dir. What do I need to do to re-write so that for each New File there is a corresponding folder path?

      Pointer re choroba's answer: perlre, perlretut, etc. As you've written the regex, it's effectively a noop because you haven't assigned a value to $dir.

      Beyond that, it may be that your intent and the regex's behavior don't agree. The \n is the wrong way to tackle the end of a line -- if, in fact, you need to anchor to an EOL... but you haven't offered any information to suggest it's needed at all.

      So, perhaps you want something like this (after assigning a value to $dir):

      $dir =~ m/([a-z:]+).*?/; $dir = $1; print $dir;

      The parens capture to $1 the content matching a-z & colon more than one time... for ex, "C:"

        Thanks for this. "Example" - is a typical log file entry I have:

        New Dir 16 x:\xxxxxx\xxx\ New File 126862 xxxxxxxxxxxxxxxxxxxxxxx.xxx New File 48640 xxxxxxxxxxxxxxxxxxxxxxxxx.xxx New File 96494 xxxxxxxxxxxxxxxxxxxxxx.xxx New File 105466 xxxxxxxxxxxxx.xxx New File 653655 xxxxxxxxxx.xxx New File 542396 xxxxxxxxxxxxxx.xxx New Dir 6 y:\yyyyyyyyy\yyyyyyyyyyy\yyyyyyy\ New File 41984 yyyyyyyyyyyyyyyyyy.yyy New File 10007 yyyyyyyyyyyyyyy.yyy New File 1.3 m yyyyyy.yyy

        "Result" - what I want to achieve is this:

        New Dir 16 x:\xxxxxx\xxx\ New File x:\xxxxxx\xxx\ 126862 xxxxxxxxxxxxxxxxxx +xxxxx.xxx New File x:\xxxxxx\xxx\ 48640 xxxxxxxxxxxxxxxxxx +xxxxxxx.xxx New File x:\xxxxxx\xxx\ 96494 xxxxxxxxxxxxxxxxxx +xxxx.xxx New File x:\xxxxxx\xxx\ 105466 xxxxxxxxxxxxx.xxx New File x:\xxxxxx\xxx\ 653655 xxxxxxxxxx.xxx New File x:\xxxxxx\xxx\ 542396 xxxxxxxxxxxxxx.xxx New Dir 6 y:\yyyyyyyyy\yyyyyyyyyyy\yyyyyyy\ New File y:\yyyyyyyyy\yyyyyyyyyyy\yyyyyyy\ 41984 + yyyyyyyyyyyyyyyyyy.yyy New File y:\yyyyyyyyy\yyyyyyyyyyy\yyyyyyy\ 10007 + yyyyyyyyyyyyyyy.yyy New File y:\yyyyyyyyy\yyyyyyyyyyy\yyyyyyy\ 1.3 m + yyyyyy.yyy

        It's almost there except I can't get the full folder path to match its associated file(s)

        To get $dir to work, does that go within my loop?