Re^2: Add numbers in log domain

My interpretation of the OP is: Given two (log) values X & Y where both are the logs to the same (unspecified) base: B; is it possible to derive Z, such that Z = logB( B^X + B^Y ); without going through the exponentiation step.

Eg.

X = logB( x ) = 2.51294159473206;

Y = logB( y ) = 2.95544864408182;

Z = logB( x + y ) = 3.51294159473206;

Is it possible to derive Z without discovering x & y by 'antilogging' X & Y?

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'

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The start of some sanity?

Comment on Re^2: Add numbers in log domain

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Re^3: Add numbers in log domain by pRaNaV (Novice) on Jun 05, 2012 at 05:59 UTC
Sorry, for not being clear. Yes, BrowserUK is right. I wan't to know how this (log(x + y)) can be done in perl without using exponentiation (base^x, base^y etc.).	[reply]