in reply to referencing list
Just as a note: using $a and $b as variables outside of the sort() function is generally a bad idea.
To answer your question, yes it is possible, but you don't need references for that:
my @x = ( 1, 2, undef ); $x[2] = $x[0] + $x[1]; print @x, "\n";
Or is that not what you are looking for?
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