in reply to Re: Calculating CRC8 using Digest::CRC
in thread Calculating CRC8 using Digest::CRC

It was given to me by someone else whose source REALLY should be accurate. Since 2 other Monks are telling me otherwise, however, I'll be grilling him about his confidence in his source tomorrow.

Thanks!

Kaiti
Swiss Army Nerd
  • Comment on Re^2: Calculating CRC8 using Digest::CRC

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Re^3: Calculating CRC8 using Digest::CRC
by AnomalousMonk (Archbishop) on Jun 07, 2012 at 18:35 UTC

    Just to be really, really clear about the point that Athanasius is making...
    The two character string '7A' consists (in ASCII) in the hex bytes 0x37 and 0x41 (the characters '7' and 'A' respectively). OTOH, it is possible to have a single character ASCII string that consists in the single hex byte 0x7A (the character 'z').
    In the example you give in your OP, which is which?

[reply]

      Y'all are right, and this is why I probably should have waited until morning (or at least after dinner) to post my question... :-)

      It is not a string (I reverted to plain English, not Computer English) - 7A......0 *is* the hex.

      Mea culpa, sorry I wasn't clearer.
      Kaiti
      Swiss Army Nerd
[reply]

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