Re^2: How to declare arrays and scalars together?

"Remember why you can not pass multiple arrays to a subroutine?"

except, one uses reference like so:

my $arr1_ref = [ 1, 2, 3 ];
my $arr2_ref = [ 10, 9, 8, 7 ];

load_arr( $arr1_ref, $arr2_ref );    ## load multiple array references

sub load_arr {
    my ( $arr1_def, $arr2_def ) = @_;

    print join "\n", @{$arr1_def}, @{$arr2_def};
    return;
}
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Re^3: How to declare arrays and scalars together? by Anonymous Monk on Jun 18, 2012 at 16:49 UTC
You're passing array references there, not arrays.	[reply]
Re^4: How to declare arrays and scalars together? by 2teez (Vicar) on Jun 18, 2012 at 19:32 UTC
That is my point. It is possible to pass multiple arrays, using array reference.	[reply]
Re^5: How to declare arrays and scalars together? by Anonymous Monk on Jun 19, 2012 at 01:59 UTC
That is my point. It is possible to pass multiple arrays, using array reference Well, you missed the point of Re: How to declare arrays and scalars together? which is, you're only passing lists, you cannot pass an array, an array and an arrayref aren't identical, you need to de-reference an arrayref, but not an array Given `my @one = (1,1); my @two = (2,2);` This `foo( @one, @two );` is basically the same as `foo( 1,1,2,2 );` With the appropriate prototype `foo( @one, @two );` could also be basically the same as `foo( \@one, \@two );` If you use `foo( \@one, \@two );` then in sub foo you would need to write `my( $oneref, $tworef ) = @_;` which is not the same as `my( @one, @two ) = @_;` You're always passing lists to subroutines	[reply] [d/l] [select]