mhearse has asked for the wisdom of the Perl Monks concerning the following question:

Is there a way to do: 
my ($day, $month, $year) = strftime "%d %m %Y", time();

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Because that doesn't populate the array.

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Re: create array from strftime
by ikegami (Patriarch) on Jun 20, 2012 at 17:45 UTC

    Problem #1: strftime doesn't take an epoch time for argument.

    Problem #2: strftime returns a single string.

    Then there's also the fact that "3 scalars" are not "an array".

    Solution: 

    my ($day, $month, $year) = (localtime)[3,4,5];
$month += 1;
$year  += 1900;

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    localtime.

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[d/l]
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      Or read the output of strftime(3). :)
      Here's another example: 
      use POSIX qw(strftime); # POSIX is your friend
# see man strftime(3) for format options
my $gmtstring = strftime "%F %H:%I:%S %z", localtime;
print $gmtstring;

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      Hope this helps.


      my $perl_version( 5.12.4 );
print $perl_version;
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[d/l]
        How does one use that to populate $day, $month and $year?
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Re: create array from strftime
by Anonymous Monk on Jun 20, 2012 at 17:44 UTC

    <serious joker>Sure, all you do is stuff some dynamite into your pants and light the fuze

    the opposite of strftime is strptime, DateTime comes with both

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