in reply to why my reg ex matches greedy?

The (.*) part is greedy because you've not used the ungreedy quantifier. The ungreedy version is (.*?).

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

In Section Seekers of Perl Wisdom