Re: Style - how to give class method call as parameter

Number 3a:

my $success = $self->do_sub_with_timeout( $deployer->extend_order_leas
+e( $order, $end_date ),
                                          $timeout );
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But there’s nothing wrong with Number 1.

Update: Seems I missed the point of the question. Thanks to Boldra and choroba for pointing out that my ‘solution’ preempts the timeout.

Athanasius <°(((>< contra mundum

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Re^2: Style - how to give class method call as parameter by Boldra (Curate) on Jun 26, 2012 at 13:44 UTC
That's not going to work, `extend_order_lease` will be executed before `do_sub_with_timeout` gets called, so there'll be no chance for it to interrupt. OP: How much code is in `do_sub_with_timeout`? Since the subroutine/method call is making it less readable, maybe there's no benefit in putting it in a subroutine? Maybe what you really want is a sub like `handle_timeout` which gets called if the timeout is exceeded.	[reply]
Re^2: Style - how to give class method call as parameter by choroba (Cardinal) on Jun 26, 2012 at 13:50 UTC
That's not the same. You are calling the method, not passing a reference to it.	[reply]