PerlOnTheWay has asked for the wisdom of the Perl Monks concerning the following question: 

  
     "get"
             $memd−>get($key);

           Retrieve the value for a $key.  $key should be a scalar.

           Return: value associated with the $key, or nothing.

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If a key doesn't exist, I can nothing.

If it times out, I can nothing either.

How can I distinguish these two different cases after I get nothing from Cache::Memcached::Fast::get ?

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Re: Can Cache::Memcached::Fast distinguish timeout or not existing?
by Khen1950fx (Canon) on Jun 28, 2012 at 16:39 UTC
    Something similar to this? 
    #!/usr/bin/perl 

use strict;
use warnings;
use Cache::Memcached::Fast;
use Cache::Memcached;

use constant count => 2;

my %params;
foreach my $h (@{$params{servers}}) {
    $h->{noreply} = 1 if ref($h) eq 'HASH';
}

my $another = new Cache::Memcached::Fast(\%params);

my @keys = map { "noreply-$_" } (1..count);
$another->set_multi(map { [$_, $_] } @keys);

my $res = $another->get_multi(@keys);

my $count = 0;
foreach my $k (@keys) {
    if ($res->{$k} and $res->{$k} eq $k) {
        print $res;
    }
    else {
        print "Nothing\n";
    }
}

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[reply]
[d/l]

      Something similar to this?

      Hmm, lets try that , question: Can ... distinguish timeout or not existing ?

      Answer: Something similar to this?

      Hmm, the question something similar? doesn't answer Can .. yes or no?

      Also, the code doesn't answer the question either

      Too bad

[reply]
        You didn't answer the question either. Too bad. Post your solution, please.
[reply]

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