reverse function

Sandyyy123 has asked for the wisdom of the Perl Monks concerning the following question:

Replies are listed 'Best First'.
Re: reverse function by moritz (Cardinal) on Jun 29, 2012 at 11:57 UTC
As the documentation for reverse explains, using it in scalar context does string reversal, not list reversal. Thus it joins all arguments into a string and reverses it. If you want the other output, either leave off the `scalar`, or write `print join '', reverse(1, 'ab'));` [download] Note that this behavior confuses many newcomers (though usually they wonder why `print reverse "abc";` doesn't reverse anything) and is inconsistent with how things are generally done elsewhere in Perl 5, so in Perl 6 `reverse` always reverses lists, and `flip` always reverses strings. Perl 6 - the future is here, just unevenly distributed	[reply] [d/l] [select]
Re: reverse function by daxim (Curate) on Jun 29, 2012 at 12:00 UTC
This is the documented behaviour of reverse. In scalar context, concatenates the elements of LIST and returns a string value with all characters in the opposite order.	[reply]
Re: reverse function by jethro (Monsignor) on Jun 29, 2012 at 12:02 UTC
This is a simple RTFM. Do 'perldocs -f reverse' and just read the second sentence where you are told what reverse does in scalar context	[reply]
Re^2: reverse function by Anonymous Monk on Jun 29, 2012 at 12:18 UTC
Right , like `perldoc -f reverse` says `print join(", ", reverse "world", "Hello"); # Hello, world print scalar reverse "dlrow ,", "olleH"; # Hello, world` `<tt><b>[doc://perldoc]</b> -f [doc://reverse]</tt> says`	[reply] [d/l]
Re: reverse function by uday_sagar (Scribe) on Jun 29, 2012 at 12:28 UTC
Hi Sandyyy123 You can visit this page and can read the first para. You get the expected result without "scalar" in your code. `print (reverse(1,"ab"));`	[reply] [d/l]