Re: Can't use string ("16") as a HASH ref while "strict refs" in use

The whole of

my @chr_temp=split //,$arr[0];
for(1..3)
{
    shift(@chr_temp);
}
$arr[0]=join("",@chr_temp);
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can be replaced by:

$arr[0] = substr($arr[0], 3);
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Now as to our problem: Are you sure, there isn't a typo in

$site_info{$arr[0]{$arr[1]}}{"value"}=$arr[3];
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and you really meant

$site_info{$arr[0]}{$arr[1]}{"value"}=$arr[3];
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CountZero

A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James

My blog: Imperial Deltronics

Comment on Re: Can't use string ("16") as a HASH ref while "strict refs" in use Select or Download Code

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Re^2: Can't use string ("16") as a HASH ref while "strict refs" in use by thudzj (Initiate) on Aug 23, 2012 at 02:55 UTC
Thanks a lot! I checked it several times to find it out! This is a stupid mistake!	[reply]