Re: XML::Simple usage question

Congratulations! You've completed the first level! Are you ready to play level two? XML::LibXML.

You appear to have outgrown the facilities that XML::Simple offers. You may wish to read Stepping up from XML::Simple to XML::LibXML.

use 5.010;
use XML::LibXML 1.94;

my $xml = XML::LibXML->load_xml(IO =>\*DATA);

foreach my $element ($xml->findnodes("/a/*"))
{
    say "Got ", $element->tagName;
    if ($element->tagName eq 'b')
    {
        say "  type is ", $element->{type};
    }
}

__DATA__
<a>
    <b type="1"/>
    <b type="2"/>
    <c/>
    <b type="3"/>
</a>
[download]

Output is...

Got b
  type is 1
Got b
  type is 2
Got c
Got b
  type is 3

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

Comment on Re: XML::Simple usage question Download Code

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Re^2: XML::Simple usage question by gri6507 (Deacon) on Jul 13, 2012 at 21:26 UTC
Thanks for the reply! I've taken the time between posting and your response to dive much deeper into XML than I have before. What I think I want can be accomplished with XPath. I believe your solution does something similar. Here's what I came up with so far. Please chime in on my approach. First, though, I have to clarify that my original XML file example was not 100% representative of my structure. It looks more like this `<a> <b id='id1' type="1"/> <b id='id2' type="1.5"/> <b id='id3' type="2"/> <c id='id4'/> <b id='id5' type="3"/> </a>` [download] Then, I can use XML::XPath to get what I want using the following `use warnings; use strict; use XML::XPath; use XML::XPath::XMLParser; my $xmlFile = "try.xml"; # create an object to parse the file and field XPath queries my $xpath = XML::XPath->new(filename => $xmlFile) \|\| die "Problem: $!\ +n"; # look for the preceding sibling node to the one in question my $nodeset = $xpath->find('//[@id=' . "'id4']/preceding-sibling::[1 +]"); foreach my $node ( $nodeset->get_nodelist ) { print XML::XPath::XMLParser::as_string( $node ) . "\n"; }` [download]	[reply] [d/l] [select]

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Re^2: XML::Simple usage question
by gri6507 (Deacon) on Jul 13, 2012 at 21:26 UTC

Here's what I came up with so far. Please chime in on my approach. First, though, I have to clarify that my original XML file example was not 100% representative of my structure. It looks more like this

<a>
    <b id='id1' type="1"/>
    <b id='id2' type="1.5"/>
    <b id='id3' type="2"/>
    <c id='id4'/>
    <b id='id5' type="3"/>
</a>
[download]

use warnings;
use strict;
use XML::XPath;
use XML::XPath::XMLParser;

my $xmlFile = "try.xml";

# create an object to parse the file and field XPath queries
my $xpath = XML::XPath->new(filename => $xmlFile) || die "Problem: $!\
+n";

# look for the preceding sibling node to the one in question
my $nodeset = $xpath->find('//*[@id=' . "'id4']/preceding-sibling::*[1
+]");
foreach my $node ( $nodeset->get_nodelist ) {
    print XML::XPath::XMLParser::as_string( $node ) . "\n";
}
[download]

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