Regexp question,get 2nd match

cztmonk has asked for the wisdom of the Perl Monks concerning the following question:

Good Morning Monks. I have a logfile containing

bla bla IP address:port bla bla IP address:port
[download]

I have this code to get the 1st IP/port. How do I get the 2nd one?

use strict;
use warnings;
use autodie;

my @ipaddress;
my $filename = "router.log";
my $myip     = "10.0.0.";
my $count    = 0;

open my $f, "<", $filename;
while(<$f>){
  $count++;
  while (/$myip/g){
    if (m/(\d+\.\d+\.\d+\.\d+\:\d+)/){
      push @ipaddress,$1;
    }
  }
}
close $f;
[download]

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Re: Regexp question,get 2nd match by johngg (Canon) on Jul 24, 2012 at 10:15 UTC
Please clarify whether you want all the IP addresses on a line that contains an address on your 10.0.0 network or whether you only want to capture addresses on that network. Note that when you look for a line containing "10.0.0" you should quotemeta your `$myip` variable because the regex `/10.0.0/` will also match 100000 and 10a0b0 since the dot will match any character. Cheers, JohnGG	[reply] [d/l] [select]
Re^2: Regexp question,get 2nd match by cztmonk (Monk) on Jul 24, 2012 at 10:27 UTC
I want all IP addresses / ports who are accessing 10.0.0.z Thanks for the quotemeta tip, I did not know this one... Regards.	[reply]
Re: Regexp question,get 2nd match by davido (Cardinal) on Jul 24, 2012 at 11:12 UTC
Assuming the IP address will always have a port number appended to it: `use Regexp::Common qw( net ); while ( <DATA> ) { while ( m/($RE{net}{ipv4}:\d+)/g ) { print $1, "\n"; } } __DATA__ [LAN access from remote] from 213.114.117.222:52582 to 10.0.0.3:5697, +Monday, July 23,2012 19:42:26` [download] If you're only interested in those IP's that access "10.0.0.x:y", this will do it: `while( m/(10\.0\.0\.\d+:\d+)/ ) { print $1, "\n"; }` [download] If you want something else then let's back up and discuss what you're trying to accomplish first. Dave	[reply] [d/l] [select]
Re: Regexp question,get 2nd match by Corion (Patriarch) on Jul 24, 2012 at 09:57 UTC
Maybe consider matching the first IP address and then something and then the second IP address? It shouldn't be hard to modify your regular expression to allow for that.	[reply]
Re: Regexp question,get 2nd match by Ratazong (Monsignor) on Jul 24, 2012 at 10:56 UTC
If `(\d+\.\d+\.\d+\.\d+\:\d+)` matches one ip-address, then `(\d+\.\d+\.\d+\.\d+\:\d+)(\d+\.\d+\.\d+\.\d+\:\d+)` will match two(). The only thing you have to consider that there are some other characters in between. You may get them with `.?`. So your final code could be: `if (m/(\d+\.\d+\.\d+\.\d+\:\d+).?(\d+\.\d+\.\d+\.\d+\:\d+)/){ push @ipaddress,$2;` [download] HTH, Rata update:* (*) well, not exactly, as there is a seperator missing between both (and the regex-engine cannot determine where ip1 ends and where ip2 starts) ... but that is taken care off in the next step...	[reply] [d/l] [select]
Re: Regexp question,get 2nd match by desemondo (Hermit) on Jul 24, 2012 at 09:59 UTC
Also, you are far more likely to get a helpful response by providing actual source input data.	[reply]
Re^2: Regexp question,get 2nd match by cztmonk (Monk) on Jul 24, 2012 at 10:08 UTC
Here is my source input `[LAN access from remote] from 213.114.117.222:52582 to 10.0.0.3:5697, Monday, July 23,2012 19:42:26`	[reply] [d/l]