Re^2: C-Style Struct?

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Re^3: C-Style Struct? by Anonymous Monk on Aug 08, 2012 at 18:30 UTC
You could add accessors to the object. Like this: `sub count { my $self = shift; return $self->[0] unless @_; $self->[0] = shift; } # ... $cc->count(42); print $cc->count;` [download]	[reply] [d/l]
Re^3: C-Style Struct? by xiaoyafeng (Deacon) on Aug 08, 2012 at 23:57 UTC
changed it, Thanks for your reminding.;) I am trying to improve my English skills, if you see a mistake please feel free to reply or /msg me a correction	[reply]
Re^4: C-Style Struct? by Arunbear (Prior) on Aug 09, 2012 at 17:56 UTC
But now I can see no advantage to using your example over just using a hash ;)	[reply]
Re^5: C-Style Struct? by xiaoyafeng (Deacon) on Aug 10, 2012 at 01:11 UTC
But now I can see no advantage to using your example over just using a hash ;) No, My way is using a perl object to create a struct, every struct created by this has the same elements and spawned by the same creator. `my %hash_1 = (number => 123, name => aa, stuff => \@xx); my %hash_2 = (number => 124, name => bb, stuff => \@yy); my %hash_3 = (number => 125, name => cc, stuff => \@zz); #if you chang +e struct, you have to change every instance. ..... ..... ..... my $aa = C_struct->new(123,'aa', [1,2,3]); my $bb = C_struct->new(234,'bb', [2,3,4]); #every instance is spawned +by the same object.` [download]	[reply] [d/l]