in reply to Re: Fisher's Exact Test
in thread Fisher's Exact Test

I think it is correct. It is justified because $ts implies one-side test, so the p-value is indeed 1. Hao

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Re^3: Fisher's Exact Test
by list (Initiate) on Jun 05, 2021 at 13:54 UTC
    I think it is wrong. $ts means two-side, not one-side.
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