Re^4: Regex in json: escaping forward slash

Thanks for your reply. I made a poor assumption. I was under the impression that:

my $regex = ".*/home/members/index.htm.*";
if (/$regex/)
[download]

Was the same as

if (/.*/home/members/index.htm.*/)
[download]

Which would fail. I was wrong!

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Re^5: Regex in json: escaping forward slash by davido (Cardinal) on Aug 22, 2012 at 23:42 UTC
perlop (Gory Details of Parsing Quoted Constructs): "The most important Perl parsing rule is the first one discussed below: when processing a quoted construct, Perl first finds the end of that construct, then interprets its contents." `m//` is a quoted construct. So the "end" will be found before the contents are interpreted (including interpolated). Now if you say, "`m/a/b/`", the problem is that the end is found between 'a' and 'b'. But when you say, `$c='/'`, and then `m/a${c}b/`, the end is found after 'b', and later the interpolation of `$c` takes place. Dave	[reply] [d/l] [select]

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Re^5: Regex in json: escaping forward slash
by davido (Cardinal) on Aug 22, 2012 at 23:42 UTC

perlop (Gory Details of Parsing Quoted Constructs): "The most important Perl parsing rule is the first one discussed below: when processing a quoted construct, Perl first finds the end of that construct, then interprets its contents."

m// is a quoted construct. So the "end" will be found before the contents are interpreted (including interpolated). Now if you say, "m/a/b/", the problem is that the end is found between 'a' and 'b'. But when you say, $c='/', and then m/a${c}b/, the end is found after 'b', and later the interpolation of $c takes place.

Dave

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