Re^2: Finding connected components in a graph.

Hi there, As per your suggestion I added these two lines, but as you can see in the output section the results are totally invalid.

print "First connected component == $subgraphs[1]\n";
print "Number of connected components== $#subgraphs\n";
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-----OUTPUT----------

5
----connected components---------------
-
  - c
  - b
  - a
-
  - e
  - d
First connected component == ARRAY(0x9a8e308)
Number of connected components== 1
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Re^3: Finding connected components in a graph. by SuicideJunkie (Vicar) on Oct 02, 2012 at 18:32 UTC
Yes. The subgraph is an array reference. Dig in! `foreach my element (@{ $subgraphs[0] }) {...}` As expected, the last index in your two element array is 1. The other index is 0. As I wrote, you want to print 0+@subgraphs, or more explicitly, scalar(@subgraphs).	[reply] [d/l]