I have been trying to use the regex substitution modifier "r" to work with no success. I finally tried running the examples from perlrequick and cannot get them to work either. This example is from the section titled "The non-destructive modifier s///r". 

$x = "I like dogs.";
$y = $x =~ s/dogs/cats/r;
print "$x $y\n"; # prints "I like dogs. I like cats."

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When I run it I get this error.I get the same error using strict and declaring the variables. 

Bareword found where operator expected at r.pl line 2, near "s/dogs/ca
+ts/r"
syntax error at r.pl line 2, near "s/dogs/cats/r"

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Can anyone tell me what's wrong?

In reply to Regex substitution modifier /r by nonsequitur

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