in reply to Why is the execution order of subexpressions undefined?

What we'd really like to do is outlaw goofy side-effecting code like... 
my $rv = func( $i, ++i, $i+2 );

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...but that would be a hard problem. So instead we merely say the results are undefined, and hope that it scares away anybody who wants to do something ugly like that.

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Re^2: Why is the execution order of subexpressions undefined?
by BrowserUk (Patriarch) on Apr 12, 2005 at 19:01 UTC
    What we'd really like to do is outlaw goofy side-effecting code like.

    Hey! Don't knock it. It took me hours of trial and error to come up with that example!

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