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  1. or download this
    use strict;
    my @freq;
    ...
        print qq{\n$_($freq[$_]): @{[map {"$_($ref->{$_}x)"} sort {$a <=> 
    +$b} keys %{$ref}]}};
    }
    print "\n$total total\n";
    
  2. or download this
    N frequency     consecutives(times x)
    0(178763622): 2(14480890x) 3(1449710x) 4(144353x) 5(14618x) 6(1459x) 7
    +(146x) 8(19x) 9(1x)
    ...
    8(178766722): 2(14483441x) 3(1448498x) 4(144450x) 5(14594x) 6(1448x) 7
    +(150x) 8(18x) 9(1x)
    9(178775354): 2(14481938x) 3(1446327x) 4(145687x) 5(14591x) 6(1480x) 7
    +(157x) 8(10x) 9(2x)
    1787595999 total