(Somehow I don't feel that posting nodes in a thread is the best way to have this kind of debate, but...)

I don't know how to tell you gently that you are quite mistaken.
I am only inverting two levels of keys of hashes. The values stay at the "leafs", where they were.

In other words, given hash %a as     $a{foo}{bar} = value; I am creating an "inversion" of that hash, %b, as     $b{bar}{foo} = value; No potential for loss. No values being used as keys, nor vice versa.

jdporter
...porque es dificil estar guapo y blanco.