While we're on the subject of efficiency, how could I make this a little more efficient?

if ($_ =~ /^FOO \=/) {
        $_ =~ s/^FOO \=\s//;
        $_ =~ s/\\$//;
        push @array, $_;
    }
[download]

Firstly, you don't need to reference $_ for the m// or the s///, as it is the default. Second, you can capture the bit you want in the m//. It's also better to use a different delimiter if you have /'s in your regex

push @array, $1 if m[^FOO\s=\s(.*?)/$];
[download]

should capture everything after the first space after the '=' and before the trailing '/'. If the number of spaces might vary then

push @array, $1 if m[^FOO\s+=\s+(.*?)/$];
[download]

This wouldn't harm if there is only one space before and after.

---

Examine what is said, not who speaks.

Thanks again, you have been a great help. I always learn something new when I come here.

One last thing, shouldn't I have a slash after the match character?

push @conf, $1 if m[^SSLOGGER FILE\s+=\s+(.*?)/$]; #before
push @conf, $1 if m/[^SSLOGGER FILE\s+=\s+(.*?)/$]; #after
[download]

I'm using VIM for windows and it doesn't like that string for some reason

if (s/^FOO =\s//){
    s/\\$//;
    push @array, $_;
}
[download]

Basically, the only real change for efficiency is to do the replace once instead of twice. The rest is style, though style counts. I might suggest, though, making the first one a bit less strict, something like

if (s/^FOO\s*=\s*//){
[download]

So it doesn't matter if there's more than one space, or a tab, or...whatever. But that's for your code to do with as it will.