Yes, \G is the same as \A in this context (i.e \G hasn't been set before) according to perlop (the last sentence is the most relevant sentence)

You can intermix "m//g" matches with "m/\G.../g", where "\G" is a zero-width assertion that matches the exact position where the previous "m//g", if any, left off. Without the "/g" modifier, the "\G" assertion still anchors at pos(), but the match is of course only attempted once. Using "\G" without "/g" on a target string that has not previously had a "/g" match applied to it is the same as using the "\A" assertion to match the beginning of the string.