hi guys,

Why is the following code print the \n first before the scalars ?

I wanted it like this, print $toto, => new line => print $tutu ... 

#!/usr/bin/perl -w

use strict;
use warnings;

my $toto = 'toto';
my $tutu = 'tutu';

my $deux = $toto, print "\n", $tutu;

print $deux

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In reply to simple scalars question by mitchreward

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