Hi to all, I need to substract from actual date/time 7 days. The format could be for example #031810002015 (march 18 10:00 of year 2015): 
#!/usr/bin/perl -w
#output as 031810002015 (march 18 10:00 del 2015)
($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime(time
+);
my $now = sprintf("%02d%02d%02d%02d%04d", $mon+1, $mday,$hour, $min,$y
+ear+1900);
print "$now\n";

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Thanks for your time as usuals, Nick.

In reply to substract from actual date 7 days and printout in month.days.hours.min.year by nicopelle

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